How do you print the memory address of a pointer in C?

How do you print the memory address of a pointer in C?

To print the memory address, we use ‘%p’ format specifier in C. To print the address of a variable, we use “%p” specifier in C programming language. There are two ways to get the address of the variable: By using “address of” (&) operator.

How do I print a pointer memory address?

Printing pointers. You can print a pointer value using printf with the %p format specifier. To do so, you should convert the pointer to type void * first using a cast (see below for void * pointers), although on machines that don’t have different representations for different pointer types, this may not be necessary.

What is the size of pointer in C?

The size of a pointer in C/C++ is not fixed. It depends upon different issues like Operating system, CPU architecture etc. Usually it depends upon the word size of underlying processor for example for a 32 bit computer the pointer size can be 4 bytes for a 64 bit computer the pointer size can be 8 bytes.

What does & Means in C?

C++Server Side ProgrammingProgramming. The & symbol is used as an operator in C++. It is used in 2 different places, one as a bitwise and operator and one as a pointer address of operator.

How do you declare malloc?

Syntax: ptr = (cast-type*) malloc(byte-size) For Example: ptr = (int*) malloc(100 * sizeof(int)); Since the size of int is 4 bytes, this statement will allocate 400 bytes of memory.

What is size of FAR pointer?

A far pointer is typically 32 bit that can access memory outside current segment. To use this, compiler allocates a segment register to store segment address, then another register to store offset within current segment. Like far pointer, huge pointer is also typically 32 bit and can access outside segment.

What is the meaning of 0 in C?

\0 is zero character. In C it is mostly used to indicate the termination of a character string. Of course it is a regular character and may be used as such but this is rarely the case. The simpler versions of the built-in string manipulation functions in C require that your string is null-terminated(or ends with \0 ).

How to printf a memory address in C?

printf (“variable A is at address: %pn”, (void*)&A); The standard requires that the argument is of type void* for %p specifier. Since, printf is a variadic function, there’s no implicit conversion to void * from T * which would happen implicitly for any non-variadic functions in C. Hence, the cast is required.

How are pointers converted to characters in printf?

The value of the pointer is converted to a sequence of printing characters, in an implementation-defined manner. Whereas you are using %x, which expects unsigned int whereas &A is of type int *. You can read about format specifiers for printf from the manual. Format specifier mismatch in printf leads to undefined behaviour.

How to print an INT with length specifier?

A workaround to use %x with length specifier to print an int or unsigned int without compiler complaining about casting would be to use malloc: Alternatively you can compile with gcc -w flag to suppress those casting warnings. Thanks for contributing an answer to Stack Overflow!

How do you print the memory address of a pointer in C? To print the memory address, we use ‘%p’ format specifier in C. To print the address of a variable, we use “%p” specifier in C programming language. There are two ways to get the address of the variable: By using “address of” (&)…